# Angry Professor HackerRank Solution in C, C++, Java, Python

A Discrete Mathematics professor has a class of students. Frustrated with their lack of discipline, the professor decides to cancel class if fewer than some number of students are present when class starts. Arrival times go from on time (arrivalTime<=10) to arrived late (arrival>0).

Given the arrival time of each student and a threshhold number of attendees, determine if the class is cancelled.

Example

```N = 5

K = 3

A = [2,1,0,1,2]```

The first 3 students arrived on. The last 2 were late. The threshold is 3 students, so class will go on. Return YES.

Note: Non-positive arrival times (a[i]<=0) indicate the student arrived early or on time; positive arrival times (a[i]>0) indicate the student arrived a[i] minutes late.

Function Description

Complete the angryProfessor function in the editor below. It must return YES if class is cancelled, or NO otherwise.

angryProfessor has the following parameter(s):

• int k: the threshold number of students
• int a[n]: the arrival times of the n students

Returns

• string: either YES or NO

Input Format

The first line of input contains t, the number of test cases.

Each test case consists of two lines.

The first line has two space-separated integers,n  and k, the number of students (size of a) and the cancellation threshold.

The second line contains n space-separated integers (a[1],a[2],….,a[n]) that describe the arrival times for each student.

Constraints

• 1<=t<=10
• 1<=n<=1000
• 1<=k<=n
• 100<=a[i]<=100, where i belongs to [1,…n]

Sample Input

```2

4 3

-1 -3 4 2

4 2

0 -1 2 1

```

Sample Output

```YES

NO

```

## Angry Professor HackerRank Solution in C

```/*Angry Professor*/

#include<stdio.h>

int main()
{
int count, i, K, N, T, time;
scanf("%d", &T);
while (T--)
{
scanf("%d %d", &N, &K);
count = 0;
for (i = 0; i < N; i++)
{
scanf("%d", &time);
if (time <= 0)
count++;
}
puts((count < K) ? "YES" : "NO");
}
return 0;
}```

## Angry Professor HackerRank Solution in C++

```#include <bits/stdc++.h>
using namespace std;
int main()
{
int a; cin >> a;
for (int g=0; g<a; g++)
{
int b,c; cin >> b >> c;
int num=0;
for (int g=0; g<b; g++)
{
int d; cin >> d;
if (d<=0) num++;
}
if (num>=c)
{
cout << "NO" << '\n';
}
else cout << "YES" << '\n';
}
return 0;
}```

## Angry Professor HackerRank Solution in Java

```import java.io.BufferedReader;
import java.io.PrintWriter;
import java.util.StringTokenizer;

public class AngryProf {

public static void main(String args[] ) throws Exception {
PrintWriter w = new PrintWriter(System.out);

while(t-- > 0) {
int n = ip(st1.nextToken());
int k = ip(st1.nextToken());

int a[] = new int[n];
for(int i=0;i<n;i++)
a[i] = ip(st2.nextToken());

int count = 0;
for(int i=0;i<n;i++)
if(a[i]<=0)	count++;
w.println(count < k ? "YES" : "NO");
}

w.close();

}

public static int ip(String s){
return Integer.parseInt(s);
}

}```

## Angry Professor HackerRank Solution in Python

```for _ in xrange(input()):
n, m = map(int, raw_input().split())
A = map(int, raw_input().split())
for x in A:
if x <= 0:
m -= 1
if m <= 0:
print "NO"
else:
print "YES"```

## Angry Professor HackerRank Solution in C#

```using System;
using System.Collections.Generic;
using System.IO;
class Solution {
static void Main(String[] args) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution */

for (int i = 0; i < count; i++)
{

int numstudents = int.Parse(nk[0]);
int minnumber = int.Parse(nk[1]);

System.Diagnostics.Debug.Assert(students.Length == numstudents);

int earlystudents = 0;
foreach (string item in students)
{
int time = int.Parse(item);

if (time <= 0)
earlystudents++;
}

if (earlystudents >= minnumber)
Console.WriteLine("NO");
else
Console.WriteLine("YES");
}
}
}```

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