CamelCase HackerRank Solution in C, C++, Java, Python

There is a sequence of words in CamelCase as a string of letters,s, having the following properties:

  • It is a concatenation of one or more words consisting of English letters.
  • All letters in the first word are lowercase.
  • For each of the subsequent words, the first letter is uppercase and rest of the letters are lowercase.

Given s, determine the number of words in s.

Example

s = oneTwoThree

There are 3 words in the string: ‘one’, ‘Two’, ‘Three’.

Function Description

Complete the camelcase function in the editor below.

camelcase has the following parameter(s):

  • string s: the string to analyze

Returns

  • int: the number of words in s

Input Format

A single line containing string s.

Constraints

  • 1<=length of s<=10^5

Sample Input

saveChangesInTheEditor

 

Sample Output

5

 

Explanation

String s contains five words:

  1. save
  2. Changes
  3. In
  4. The
  5. Editor

CamelCase HackerRank Solution in C

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main(){
    char* s = (char *)malloc(10240 * sizeof(char));
    scanf("%s",s);
    int coun=0,i;
    for(i=0;i<strlen(s);i++)
    {
        if(s[i]>=65 && s[i]<=90){coun++;}
    }
    printf("%d\n",coun+1);
    return 0;
}

 

CamelCase HackerRank Solution in C++

#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <iostream>
#include <algorithm>
#include <unordered_map>

using namespace std;


int main(){
    string s;
    cin >> s;
    int t=1;
    for (int i=0;i<s.length();i++)
        if (isupper(s[i]))
        t++;
        cout<<t<<endl;
    return 0;
}

 

CamelCase HackerRank Solution in Java

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String s = in.next();
        int count = 1;
        for(int i = 0; i<s.length(); i++){
            char c = s.charAt(i);
            if(c>='A' && c<='Z') count++;
        }
        System.out.println(count);
    }
}

 

CamelCase HackerRank Solution in Python

#!/bin/python

import sys


s = raw_input().strip()
count=0
for i in s:
    if i.upper()==i:
        count+=1
print count+1

 

CamelCase HackerRank Solution in C#

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
class Solution {

    static void Main(String[] args) {

        string line = Console.ReadLine();

        int ans = 0;
        foreach (var c in line) {
            if (c < 'a') ans++;
        }

        Console.WriteLine(ans+1);
    }
}

 

Attempt CamelCase HackerRank Challenge

Link –¬†https://www.hackerrank.com/challenges/camelcase

Next HackerRank Challenge Solution 

Link –¬†https://exploringbits.com/insertion-sort-part-1-hackerrank-solution/

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